
the equivalence of two definitions of locally closed sets
Oct 24, 2025 · the equivalence of two definitions of locally closed sets Ask Question Asked 11 years, 8 months ago Modified 1 month ago
A locally $\kappa$-presentable category is also locally $\lambda ...
Dec 24, 2023 · A locally $\kappa$ -presentable category is also locally $\lambda$ -presentable for any $\lambda>\kappa$. ¹ A regular cardinal is an infinite cardinal $\kappa$ with the property …
Locally closed subspace - Mathematics Stack Exchange
Aug 19, 2020 · Locally closed subspace Ask Question Asked 5 years, 4 months ago Modified 5 years, 4 months ago
The definition of locally Lipschitz - Mathematics Stack Exchange
Actually, a continuously differentiable function is locally Lipschitz, but since the derivative isn't assumed continuous in the theorem, one has only the weaker property that might be dubbed …
algebraic geometry - Mathematics Stack Exchange
Jan 17, 2021 · My attempt so far seems to sort of blow by this, and I'm not confident it's correct - if it were true, it would seem that I can completely remove the regularity condition, which seems …
'Locally' Convex Function - Mathematics Stack Exchange
Jun 2, 2020 · My intuition suggests that a continuously differentiable function on a convex set which is locally convex everywhere should be globally convex, but I have trouble constructing …
Is locally compact space Hausdorff? - Mathematics Stack Exchange
Jan 5, 2020 · In this proof of the statement that proper maps to locally compact spaces are closed, the fact that compact subspaces of Hausdorff spaces are closed is used. However, is it …
general topology - When is a Borel measure locally finite ...
Feb 6, 2023 · Question 2: Is a Borel measure on a $\sigma$ -compact space locally finite? I've asked this question before here, and a counterexample to Question 2 is proposed, but the …
Locally finite vs. Borel measures on $\sigma$-compact Polish spaces
I can’t think of a counter example to this, but I’m having trouble proving it. My original strategy was to prove that a $\sigma$ -compact Polish space is locally compact. However, as the comments …
A continuously differentiable map is locally Lipschitz
A function is called locally Lipschitz continuous if for every x in X there exists a neighborhood U of x such that f restricted to U is Lipschitz continuous. Equivalently, if X is a locally compact …